1/4n-5-1/4n^2-5n=6/4n^2-5n

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Solution for 1/4n-5-1/4n^2-5n=6/4n^2-5n equation: 


n in (-oo:+oo)

(1/4)*n-((1/4)*n^2)-(5*n)-5 = (6/4)*n^2-(5*n) // - (6/4)*n^2-(5*n)

(1/4)*n-((1/4)*n^2)-((6/4)*n^2)-(5*n)+5*n-5 = 0

(-1/4)*n^2+(-3/2)*n^2+(1/4)*n-5*n+5*n-5 = 0

1/4*n-7/4*n^2-5 = 0

DELTA = (1/4)^2-(-5*(-7/4)*4)

DELTA = -559/16

DELTA < 0

n belongs to the empty set

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